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1. Distance from A B C Vertex Distance to C Previous Vertex A + 4 = 10B2. Vertex PATHDistance to EAABCDE4+6+5+5 = 20AABFCDE4+3+7+5+5 =24AABFGE4+3+7+4 = 18AABFCDGE4+3+7+5+4+4 = 28AABFDE4+3+3+5 = 15AABFDGE4+3+3+4+4 = 18AABCFDE6+4+7+3+5 = 25AABCFGE6+4+7+7+4 = 28AABCDGE6+4+5+4+4 = 23AABCFDE6+4+7+3+5 = 25AABCFDGE6+4+7+3+4+4 = 28AAFBCDE5+3+6+5+5 = 24AAFGE5+7+4 = 16AAFBCDGE5+3+6+5+4+4 = 27AAFDE5+3+5 = 13The shortest distance is AFDE which takes 13 minutes to get to the largest customer E3. A and F4. A B = 4A F = 55.C and D 6A - B C = 4 + 6 = 10 A - B C D = 4 + 6 + 5 = 15A B - F D = 4 + 3 + 3 = 10 A B - F - C = 4 + 3 + 7 = 14A F C D = 5 + 7 + 5 = 17A - F - D = 5 + 3 = 8A F C = 5 + 7 = 12A F B C D = 5 + 3 +6 + 5 = 197.Circled Node is D Darkened Arc is A F D 8. Adjacent No...
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